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(I)=-0.36I^2+10.8I+819
We move all terms to the left:
(I)-(-0.36I^2+10.8I+819)=0
We get rid of parentheses
0.36I^2-10.8I+I-819=0
We add all the numbers together, and all the variables
0.36I^2-9.8I-819=0
a = 0.36; b = -9.8; c = -819;
Δ = b2-4ac
Δ = -9.82-4·0.36·(-819)
Δ = 1275.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.8)-\sqrt{1275.4}}{2*0.36}=\frac{9.8-\sqrt{1275.4}}{0.72} $$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.8)+\sqrt{1275.4}}{2*0.36}=\frac{9.8+\sqrt{1275.4}}{0.72} $
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